3.19.23 \(\int \frac {(1-2 x)^{5/2} (3+5 x)^3}{(2+3 x)^3} \, dx\)

Optimal. Leaf size=135 \[ \frac {55 (1-2 x)^{3/2} (5 x+3)^3}{9 (3 x+2)}-\frac {(1-2 x)^{5/2} (5 x+3)^3}{6 (3 x+2)^2}-\frac {220}{21} (1-2 x)^{3/2} (5 x+3)^2+\frac {55 (1-2 x)^{3/2} (603 x+209)}{1134}-\frac {935}{81} \sqrt {1-2 x}+\frac {935}{81} \sqrt {\frac {7}{3}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ) \]

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Rubi [A]  time = 0.06, antiderivative size = 135, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 8, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {97, 12, 149, 153, 147, 50, 63, 206} \begin {gather*} \frac {55 (1-2 x)^{3/2} (5 x+3)^3}{9 (3 x+2)}-\frac {(1-2 x)^{5/2} (5 x+3)^3}{6 (3 x+2)^2}-\frac {220}{21} (1-2 x)^{3/2} (5 x+3)^2+\frac {55 (1-2 x)^{3/2} (603 x+209)}{1134}-\frac {935}{81} \sqrt {1-2 x}+\frac {935}{81} \sqrt {\frac {7}{3}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((1 - 2*x)^(5/2)*(3 + 5*x)^3)/(2 + 3*x)^3,x]

[Out]

(-935*Sqrt[1 - 2*x])/81 - (220*(1 - 2*x)^(3/2)*(3 + 5*x)^2)/21 - ((1 - 2*x)^(5/2)*(3 + 5*x)^3)/(6*(2 + 3*x)^2)
+ (55*(1 - 2*x)^(3/2)*(3 + 5*x)^3)/(9*(2 + 3*x)) + (55*(1 - 2*x)^(3/2)*(209 + 603*x))/1134 + (935*Sqrt[7/3]*A
rcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/81

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 97

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((a + b
*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p)/(b*(m + 1)), x] - Dist[1/(b*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n
- 1)*(e + f*x)^(p - 1)*Simp[d*e*n + c*f*p + d*f*(n + p)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f}, x] && LtQ[m
, -1] && GtQ[n, 0] && GtQ[p, 0] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p] || IntegersQ[p, m + n])

Rule 147

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_) + (f_.)*(x_))*((g_.) + (h_.)*(x_)), x_Symbol]
:> -Simp[((a*d*f*h*(n + 2) + b*c*f*h*(m + 2) - b*d*(f*g + e*h)*(m + n + 3) - b*d*f*h*(m + n + 2)*x)*(a + b*x)^
(m + 1)*(c + d*x)^(n + 1))/(b^2*d^2*(m + n + 2)*(m + n + 3)), x] + Dist[(a^2*d^2*f*h*(n + 1)*(n + 2) + a*b*d*(
n + 1)*(2*c*f*h*(m + 1) - d*(f*g + e*h)*(m + n + 3)) + b^2*(c^2*f*h*(m + 1)*(m + 2) - c*d*(f*g + e*h)*(m + 1)*
(m + n + 3) + d^2*e*g*(m + n + 2)*(m + n + 3)))/(b^2*d^2*(m + n + 2)*(m + n + 3)), Int[(a + b*x)^m*(c + d*x)^n
, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, m, n}, x] && NeQ[m + n + 2, 0] && NeQ[m + n + 3, 0]

Rule 149

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] - Dist[1
/(b*(b*e - a*f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b*c*(f*g - e*h)*(m + 1) + (
b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h)*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; Free
Q[{a, b, c, d, e, f, g, h, p}, x] && LtQ[m, -1] && GtQ[n, 0] && IntegerQ[m]

Rule 153

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(h*(a + b*x)^m*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d*f*(m + n + p + 2)), x] + Dist[1/(d*f*(m + n
+ p + 2)), Int[(a + b*x)^(m - 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*g*(m + n + p + 2) - h*(b*c*e*m + a*(d*e*(
n + 1) + c*f*(p + 1))) + (b*d*f*g*(m + n + p + 2) + h*(a*d*f*m - b*(d*e*(m + n + 1) + c*f*(m + p + 1))))*x, x]
, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && GtQ[m, 0] && NeQ[m + n + p + 2, 0] && IntegerQ[m]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin {align*} \int \frac {(1-2 x)^{5/2} (3+5 x)^3}{(2+3 x)^3} \, dx &=-\frac {(1-2 x)^{5/2} (3+5 x)^3}{6 (2+3 x)^2}+\frac {1}{6} \int -\frac {55 (1-2 x)^{3/2} x (3+5 x)^2}{(2+3 x)^2} \, dx\\ &=-\frac {(1-2 x)^{5/2} (3+5 x)^3}{6 (2+3 x)^2}-\frac {55}{6} \int \frac {(1-2 x)^{3/2} x (3+5 x)^2}{(2+3 x)^2} \, dx\\ &=-\frac {(1-2 x)^{5/2} (3+5 x)^3}{6 (2+3 x)^2}+\frac {55 (1-2 x)^{3/2} (3+5 x)^3}{9 (2+3 x)}+\frac {55}{18} \int \frac {\sqrt {1-2 x} (3+5 x)^2 (-3+72 x)}{2+3 x} \, dx\\ &=-\frac {220}{21} (1-2 x)^{3/2} (3+5 x)^2-\frac {(1-2 x)^{5/2} (3+5 x)^3}{6 (2+3 x)^2}+\frac {55 (1-2 x)^{3/2} (3+5 x)^3}{9 (2+3 x)}-\frac {55}{378} \int \frac {\sqrt {1-2 x} (3+5 x) (45+603 x)}{2+3 x} \, dx\\ &=-\frac {220}{21} (1-2 x)^{3/2} (3+5 x)^2-\frac {(1-2 x)^{5/2} (3+5 x)^3}{6 (2+3 x)^2}+\frac {55 (1-2 x)^{3/2} (3+5 x)^3}{9 (2+3 x)}+\frac {55 (1-2 x)^{3/2} (209+603 x)}{1134}-\frac {935}{54} \int \frac {\sqrt {1-2 x}}{2+3 x} \, dx\\ &=-\frac {935}{81} \sqrt {1-2 x}-\frac {220}{21} (1-2 x)^{3/2} (3+5 x)^2-\frac {(1-2 x)^{5/2} (3+5 x)^3}{6 (2+3 x)^2}+\frac {55 (1-2 x)^{3/2} (3+5 x)^3}{9 (2+3 x)}+\frac {55 (1-2 x)^{3/2} (209+603 x)}{1134}-\frac {6545}{162} \int \frac {1}{\sqrt {1-2 x} (2+3 x)} \, dx\\ &=-\frac {935}{81} \sqrt {1-2 x}-\frac {220}{21} (1-2 x)^{3/2} (3+5 x)^2-\frac {(1-2 x)^{5/2} (3+5 x)^3}{6 (2+3 x)^2}+\frac {55 (1-2 x)^{3/2} (3+5 x)^3}{9 (2+3 x)}+\frac {55 (1-2 x)^{3/2} (209+603 x)}{1134}+\frac {6545}{162} \operatorname {Subst}\left (\int \frac {1}{\frac {7}{2}-\frac {3 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )\\ &=-\frac {935}{81} \sqrt {1-2 x}-\frac {220}{21} (1-2 x)^{3/2} (3+5 x)^2-\frac {(1-2 x)^{5/2} (3+5 x)^3}{6 (2+3 x)^2}+\frac {55 (1-2 x)^{3/2} (3+5 x)^3}{9 (2+3 x)}+\frac {55 (1-2 x)^{3/2} (209+603 x)}{1134}+\frac {935}{81} \sqrt {\frac {7}{3}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )\\ \end {align*}

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Mathematica [A]  time = 0.06, size = 75, normalized size = 0.56 \begin {gather*} \frac {\sqrt {1-2 x} \left (54000 x^5-24120 x^4-17460 x^3-67962 x^2-152833 x-64943\right )}{1134 (3 x+2)^2}+\frac {935}{81} \sqrt {\frac {7}{3}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((1 - 2*x)^(5/2)*(3 + 5*x)^3)/(2 + 3*x)^3,x]

[Out]

(Sqrt[1 - 2*x]*(-64943 - 152833*x - 67962*x^2 - 17460*x^3 - 24120*x^4 + 54000*x^5))/(1134*(2 + 3*x)^2) + (935*
Sqrt[7/3]*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/81

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IntegrateAlgebraic [A]  time = 0.19, size = 99, normalized size = 0.73 \begin {gather*} \frac {935}{81} \sqrt {\frac {7}{3}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )-\frac {\left (3375 (1-2 x)^5-13860 (1-2 x)^4+17325 (1-2 x)^3+31416 (1-2 x)^2-229075 (1-2 x)+320705\right ) \sqrt {1-2 x}}{567 (3 (1-2 x)-7)^2} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[((1 - 2*x)^(5/2)*(3 + 5*x)^3)/(2 + 3*x)^3,x]

[Out]

-1/567*((320705 - 229075*(1 - 2*x) + 31416*(1 - 2*x)^2 + 17325*(1 - 2*x)^3 - 13860*(1 - 2*x)^4 + 3375*(1 - 2*x
)^5)*Sqrt[1 - 2*x])/(-7 + 3*(1 - 2*x))^2 + (935*Sqrt[7/3]*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/81

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fricas [A]  time = 1.26, size = 96, normalized size = 0.71 \begin {gather*} \frac {6545 \, \sqrt {7} \sqrt {3} {\left (9 \, x^{2} + 12 \, x + 4\right )} \log \left (-\frac {\sqrt {7} \sqrt {3} \sqrt {-2 \, x + 1} - 3 \, x + 5}{3 \, x + 2}\right ) + 3 \, {\left (54000 \, x^{5} - 24120 \, x^{4} - 17460 \, x^{3} - 67962 \, x^{2} - 152833 \, x - 64943\right )} \sqrt {-2 \, x + 1}}{3402 \, {\left (9 \, x^{2} + 12 \, x + 4\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(3+5*x)^3/(2+3*x)^3,x, algorithm="fricas")

[Out]

1/3402*(6545*sqrt(7)*sqrt(3)*(9*x^2 + 12*x + 4)*log(-(sqrt(7)*sqrt(3)*sqrt(-2*x + 1) - 3*x + 5)/(3*x + 2)) + 3
*(54000*x^5 - 24120*x^4 - 17460*x^3 - 67962*x^2 - 152833*x - 64943)*sqrt(-2*x + 1))/(9*x^2 + 12*x + 4)

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giac [A]  time = 1.10, size = 118, normalized size = 0.87 \begin {gather*} \frac {125}{189} \, {\left (2 \, x - 1\right )}^{3} \sqrt {-2 \, x + 1} - \frac {10}{27} \, {\left (2 \, x - 1\right )}^{2} \sqrt {-2 \, x + 1} - \frac {370}{243} \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - \frac {935}{486} \, \sqrt {21} \log \left (\frac {{\left | -2 \, \sqrt {21} + 6 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}\right )}}\right ) - \frac {8198}{729} \, \sqrt {-2 \, x + 1} + \frac {7 \, {\left (657 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - 1519 \, \sqrt {-2 \, x + 1}\right )}}{2916 \, {\left (3 \, x + 2\right )}^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(3+5*x)^3/(2+3*x)^3,x, algorithm="giac")

[Out]

125/189*(2*x - 1)^3*sqrt(-2*x + 1) - 10/27*(2*x - 1)^2*sqrt(-2*x + 1) - 370/243*(-2*x + 1)^(3/2) - 935/486*sqr
t(21)*log(1/2*abs(-2*sqrt(21) + 6*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) - 8198/729*sqrt(-2*x + 1) + 7
/2916*(657*(-2*x + 1)^(3/2) - 1519*sqrt(-2*x + 1))/(3*x + 2)^2

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maple [A]  time = 0.01, size = 84, normalized size = 0.62 \begin {gather*} \frac {935 \sqrt {21}\, \arctanh \left (\frac {\sqrt {21}\, \sqrt {-2 x +1}}{7}\right )}{243}-\frac {125 \left (-2 x +1\right )^{\frac {7}{2}}}{189}-\frac {10 \left (-2 x +1\right )^{\frac {5}{2}}}{27}-\frac {370 \left (-2 x +1\right )^{\frac {3}{2}}}{243}-\frac {8198 \sqrt {-2 x +1}}{729}-\frac {14 \left (-\frac {73 \left (-2 x +1\right )^{\frac {3}{2}}}{2}+\frac {1519 \sqrt {-2 x +1}}{18}\right )}{81 \left (-6 x -4\right )^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-2*x+1)^(5/2)*(5*x+3)^3/(3*x+2)^3,x)

[Out]

-125/189*(-2*x+1)^(7/2)-10/27*(-2*x+1)^(5/2)-370/243*(-2*x+1)^(3/2)-8198/729*(-2*x+1)^(1/2)-14/81*(-73/2*(-2*x
+1)^(3/2)+1519/18*(-2*x+1)^(1/2))/(-6*x-4)^2+935/243*arctanh(1/7*21^(1/2)*(-2*x+1)^(1/2))*21^(1/2)

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maxima [A]  time = 1.06, size = 110, normalized size = 0.81 \begin {gather*} -\frac {125}{189} \, {\left (-2 \, x + 1\right )}^{\frac {7}{2}} - \frac {10}{27} \, {\left (-2 \, x + 1\right )}^{\frac {5}{2}} - \frac {370}{243} \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - \frac {935}{486} \, \sqrt {21} \log \left (-\frac {\sqrt {21} - 3 \, \sqrt {-2 \, x + 1}}{\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}}\right ) - \frac {8198}{729} \, \sqrt {-2 \, x + 1} + \frac {7 \, {\left (657 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - 1519 \, \sqrt {-2 \, x + 1}\right )}}{729 \, {\left (9 \, {\left (2 \, x - 1\right )}^{2} + 84 \, x + 7\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(3+5*x)^3/(2+3*x)^3,x, algorithm="maxima")

[Out]

-125/189*(-2*x + 1)^(7/2) - 10/27*(-2*x + 1)^(5/2) - 370/243*(-2*x + 1)^(3/2) - 935/486*sqrt(21)*log(-(sqrt(21
) - 3*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) - 8198/729*sqrt(-2*x + 1) + 7/729*(657*(-2*x + 1)^(3/2) -
1519*sqrt(-2*x + 1))/(9*(2*x - 1)^2 + 84*x + 7)

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mupad [B]  time = 0.06, size = 92, normalized size = 0.68 \begin {gather*} -\frac {8198\,\sqrt {1-2\,x}}{729}-\frac {370\,{\left (1-2\,x\right )}^{3/2}}{243}-\frac {10\,{\left (1-2\,x\right )}^{5/2}}{27}-\frac {125\,{\left (1-2\,x\right )}^{7/2}}{189}-\frac {\frac {10633\,\sqrt {1-2\,x}}{6561}-\frac {511\,{\left (1-2\,x\right )}^{3/2}}{729}}{\frac {28\,x}{3}+{\left (2\,x-1\right )}^2+\frac {7}{9}}-\frac {\sqrt {21}\,\mathrm {atan}\left (\frac {\sqrt {21}\,\sqrt {1-2\,x}\,1{}\mathrm {i}}{7}\right )\,935{}\mathrm {i}}{243} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((1 - 2*x)^(5/2)*(5*x + 3)^3)/(3*x + 2)^3,x)

[Out]

- (21^(1/2)*atan((21^(1/2)*(1 - 2*x)^(1/2)*1i)/7)*935i)/243 - (8198*(1 - 2*x)^(1/2))/729 - (370*(1 - 2*x)^(3/2
))/243 - (10*(1 - 2*x)^(5/2))/27 - (125*(1 - 2*x)^(7/2))/189 - ((10633*(1 - 2*x)^(1/2))/6561 - (511*(1 - 2*x)^
(3/2))/729)/((28*x)/3 + (2*x - 1)^2 + 7/9)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**(5/2)*(3+5*x)**3/(2+3*x)**3,x)

[Out]

Timed out

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